if sec thetha+tanthetha=x find tanthetha
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p in place of theta
x2=square for ur understanding
secp=x-tanp
sec2p=x2-2*x*tanp+tan2p
sec2p-tan2p=x2-2*tanp-1=0
2*x*tanp=x2-1
tanp=(x2-1)
x2=square for ur understanding
secp=x-tanp
sec2p=x2-2*x*tanp+tan2p
sec2p-tan2p=x2-2*tanp-1=0
2*x*tanp=x2-1
tanp=(x2-1)
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