Math, asked by khanazhar0555, 3 months ago

If sec thit

a =13/21
find the values
of other
trigometric ratios.​

Answers

Answered by sudhanshudhek76
3

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SecA = 13/21 = H/B

so,

cosA = 21/13 = B/H

Using Pythagoras Theorem

H^2 = P^2 + B^2

13^2 = P^2 + 21^2

169 = P^2 + 441

P^2 = 441 - 169

P^2 = 472

P = _/472

P = 16_/2

__________________________

SinA = P/H = (16_/2)/13

CosA = B/H = 21/13

TanA = P/B = (16_/2)/21

__________________________

CosecA = H/P = 13/(16_/2)

SecA = H/B = 13/21

CotA = B/P = 21/(16_/2)

__________________________

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