Question

if sec tita+tan tita=p ,then what is the value of sec tita-tan tita​

Answer 1

Answer:

Hi ,

Here I am using A instead of theta .

It is given that ,

Sec A + tan A = p ---( 1 )

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By Trigonometric identity :

Sec²A - tan² A = 1

Algebraic identity :

a² - b² = ( a + b )( a - b )

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Sec² A - tan² A = 1

( SecA + tan A )( secA - tanA ) = 1

p × ( sec A - tan A ) = 1 [ from ( 1 ) ]

Sec A - tan A = 1/p

I hope this helps you.

: )

Answer 2

Answer:

hope it helps you

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