Question

if sec x =2 and 3π/2<x<2π find the value of 1+ tan x +cosec x /1+ cot x -cosec x​

Answer 1

Answer:

-4/√3+1

Step-by-step explanation:

secx=2

x=π/3

note:in 3rd quadrant tan,cosec,cot is negative.

therefore,

1+ tan x +cosec x /1+ cot x -cosec x

=1-√3-2/√3/(1-1/√3+2/√3)

=1-√3-(2/√3)÷(√3+1)/√3

=1-√3-(2/√3+1)

= -2-2/√3+1

= -4/√3+1