If sec x + tan x = 22/7 then,
A. The value of tan x/2 = 29/15
B. The value of tan x/2 = 5/29
C. The value of cosec x + cot x = 29/15
D. The value of cosec x + cot x = 15/29
Answers
Answered by
7
ANSWER
..........................
tan p = sin p/cos p
sec p + tan p = (1 + sin p /cos p
So, we can say that 1+sin p= 22, and cos p = 7
cosec p 1/sin x
cot p= cos p sin p
cosec p+ cot p = (1+cos p)/sin p
From above, 1+cos p = 1+7 = 8
sin p 1 + sin p) - 1 = 22 - 1 = 21
So, cosec p + cot p= (1+cos p)/sin p= 8/21 = m/n
So, m+n = 8+21 = 29.
..........................
tan p = sin p/cos p
sec p + tan p = (1 + sin p /cos p
So, we can say that 1+sin p= 22, and cos p = 7
cosec p 1/sin x
cot p= cos p sin p
cosec p+ cot p = (1+cos p)/sin p
From above, 1+cos p = 1+7 = 8
sin p 1 + sin p) - 1 = 22 - 1 = 21
So, cosec p + cot p= (1+cos p)/sin p= 8/21 = m/n
So, m+n = 8+21 = 29.
Similar questions