Math, asked by Anonymous, 1 year ago

If sec x + tan x = 22/7 then,

A. The value of tan x/2 = 29/15

B. The value of tan x/2 = 5/29

C. The value of cosec x + cot x = 29/15

D. The value of cosec x + cot x = 15/29

Answers

Answered by Anonymous
7
ANSWER
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tan p = sin p/cos p
sec p + tan p = (1 + sin p /cos p
So, we can say that 1+sin p= 22, and cos p = 7 

cosec p 1/sin x 
cot p= cos p sin p
cosec p+ cot p = (1+cos p)/sin p
From above, 1+cos p = 1+7 = 8 
sin p 1 + sin p) - 1 = 22 - 1 = 21 
So, cosec p + cot p= (1+cos p)/sin p= 8/21 = m/n 
So, m+n = 8+21 = 29.
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