If sec(x)+tan(x)=p then prove that sin(x)=(p^2-1)/(p^2+1)
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★ TRIGONOMETRIC EQUATIONS ★
☣ p²-1 = 2TAN²x + 2 SEC(x)TAN(x)
☣ p²+1= 2SEC²x + 2 SEC(x)TAN(x)
☣ p²-1/p²+1 = 2TAN(x) [ TAN(x) + SEC (x) ]
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2SEC(x) [ SEC(x) + TAN(x) ]
☣ TAN(x) / SEC(x) = SIN ( x)
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☣ p²-1 = 2TAN²x + 2 SEC(x)TAN(x)
☣ p²+1= 2SEC²x + 2 SEC(x)TAN(x)
☣ p²-1/p²+1 = 2TAN(x) [ TAN(x) + SEC (x) ]
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2SEC(x) [ SEC(x) + TAN(x) ]
☣ TAN(x) / SEC(x) = SIN ( x)
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