Question

if sec(y/1-x)=a then find dy/dx​

Answer 1

Step-by-step explanation:

We have,

$\sec( \frac{y}{1 - x} ) = a$

Differentiating both sides,

$= > \sec( \frac{y}{1 - x} ) \tan( \frac{y}{1 - x} ) . \frac{d}{dx} ( \frac{y}{1 - x} ) = 0$

Since, sec(y/1-x)=a,

$= > a \sqrt{ {a}^{2} - 1} .( \frac{(1 - x) \frac{dy}{dx} - y( - 1)}{ {(1 - x)}^{2} } ) = 0$

$= > \frac{dy}{dx} (1 - x) + y = 0$

$= > \frac{dy}{dx} = \frac{y}{x - 1}$

Hope this will help you.....!