Question

If sec²θ (1 + sin θ) (1 − sin θ) = k, then find the value of k.

Answer 1

Answer:

The value of k  is 1 .  

Step-by-step explanation:

Given : sec²θ (1 + sin θ) (1 − sin θ) = k

sec²θ [(1 + sin θ) (1 − sin θ)] = k

sec²θ (1 − sin² θ)  = k

[By using identity , (a + b) (a - b) = a² - b²]

sec² θ (cos² θ)  = k  

[By using the identity, (1 - sin²θ) = cos²θ]

1/cos²θ × cos²θ = k

[By using , secθ = 1/ cosθ]

1 = k

k = 1 Hence, the value of k  is 1 .  

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Answer 2

Here is your answer bro hope it helps you