If sec²θ(1+sinθ) (1-sinθ)=k,then find the value of k
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sec*2theta (1+ sin theta)(1-sin theta )
sec*2 theta (1-sin*2 theta )
sec*2 theta cos*2 theta
as sec is the reciprocal of cos so
k=1
sec*2 theta (1-sin*2 theta )
sec*2 theta cos*2 theta
as sec is the reciprocal of cos so
k=1
preetsaini6913pbrkbw:
thanks
Answered by
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sec^2#(1-sin^2#)
sec^2#.cos^2#=k
k=1
#= thetha cause thetha symbol is not given in keyboard
sec^2#.cos^2#=k
k=1
#= thetha cause thetha symbol is not given in keyboard
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