if sec2 (2x+5/3)=tan3 (5x+2/3)=1 then find the value of x
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Answer:
sin2(3x+45)+cos2(2x+60)=1
∴sin2(3x+45)=1−cos2(2x+60)
∴sin2(3x+45)=sin2(2x+60) ............. [since 1−cos2θ=sin2θ]
∴3x+45=2x+60
∴x=15
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