Question

if sec²A (1+sinA) (1-sinA) = K, find the value of k

Answer 1

HEY FRIEND

HERE IS YOUR ANSWER

sec²A (1+sinA) (1-sinA) =k

[USING (a+b)(a-b) =a²-b²]

sec²A (1-sin²A) =k

[USING cos²A+sin²A=1]

sec²A×cos²A=k

[USING sec²A=1/cos²A]

(1/cos²A) × cos²A=k

k=1

HOPE THIS HELPS YOU

Answer 2

Hi friend,

Here is your answer,
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sec²A (1+sinA) (1-sinA) = K

=> sec²A(1-sin²A) = K                       {(a-b)(a+b)=a² - b²}

=> sec²A . cos²A = K                         {cos²A + sin²A = 1}

=>      1       ₓ  cos²A  =  K
      cos²A

=> 1  =  K


Ans: K = 1 
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