if sec2A = cosec A -42 findA
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So When We Solve this Question,we get:- Sec 5A=Sec 90-(A-36) Therefore,Sec 5A=Sec (90-A+36) Sec 5A=Sec (126-A) Therefore,5A=126-A 6A=126 A=2
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Hello..
= Sec 2A = cosec (A-42°)
= cosec(90°-2A) = cosec (A-42°)
= 90°-2A = A-42°
= 90°+42° = A+2A
= 132° = 3A
= 132\ 3 = A
= 44° = A
Hope it helps....
= Sec 2A = cosec (A-42°)
= cosec(90°-2A) = cosec (A-42°)
= 90°-2A = A-42°
= 90°+42° = A+2A
= 132° = 3A
= 132\ 3 = A
= 44° = A
Hope it helps....
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