If sec2A = cosec (A - 42), where 2A is an acute angle, find the value of A.
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Answered by
164
Given that,
Sec 2A= cosec (A - 42)
Cosec (90 - 2A)= cosec (A - 42) [∵, cosec (90°- θ)= sec θ]
Comparing angles
90 - 2A= A - 42
90 + 42= A + 2A
132 = 3A
A = 132/3
2A = 88
A = 88/2
Hence, the value of A = 44, which is an acute angle.
Answered by
72
90 + 42 = 2 a + a
132 = 3 a
a = 132/3
a = 44
It is an acute angle
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132 = 3 a
a = 132/3
a = 44
It is an acute angle
please subscribe to my channel➡️Ronit Antil
BeBrainly
@riskyjaaat
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