if sec²thetha(1+sin thetha)(1-sin thetha)=k, find the values of k
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let theta be a (as optional)
sec²a(1+sina)(1-sina)=k
sec²a(1-sin²a)=k
sec²a×cos²a=k
1=k (sec²a ×cos²a=1)
hence, k =1 Ans
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