If sec6A=cosec(A+6),where 6A is an acute angle, find the value of A
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Solution :
Given sec6A = cosec( A + 6 )
=> Cosec( 90 - 6A ) = cosec( A + 6 )
=> 90 - 6A = A + 6
=> -6A - A = 6 - 90
=> -7A = -84
=> A = ( -84 )/( -7 )
=> A = 12
Therefore ,
A = 12
••••
Given sec6A = cosec( A + 6 )
=> Cosec( 90 - 6A ) = cosec( A + 6 )
=> 90 - 6A = A + 6
=> -6A - A = 6 - 90
=> -7A = -84
=> A = ( -84 )/( -7 )
=> A = 12
Therefore ,
A = 12
••••
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