Question

If secA(1 + sinA) (1 – sin A) = k, then find the value of k.​

Answer 1

Answer:

secA(1 + sinA) (1 – sin A) = k

=> secA(1-sin²A) = k

| (a+b)(a - b) = a²-b²

Therefore, secA×cos²A = k

| 1+sin²A = cos²A

Therefore, 1/cosA × cos²A = k

| secA = 1/cosA

Therefore, cosA = k