Question

if secA =13÷5 show that 2sinA-3cosA÷4sinA-9cosA=3
who can answer this i will mark as brainlist​

Answer 1

Step-by-step explanation:

sec A = 13/5

=> hypotenuse = 13 and base = 5 therefore by Pythagoras theorem, perpendicular will be 12

sin A = 12/13, cos A = 5/13, plugging these values in the given equation,

LHS = (2*12/13 - 3*5/13) / (4*12/13 - 9*5/13)

=> (24/13 - 15/13) / (48/13 - 45/13)

=> (9/13) / (3/13)

=> 9/13 × 13/3

=> 3 = RHS

hence proved