If secA=17/8, prove that 1- 2 sin^2 A = 2cos^2A-1
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through secA you can drive cosA as cosA= 1/secA
therefore cosA=8/17
through this you can calculate sinA using the triangle properties and putting the values in both the sides
you can either do it another way
that is bu solving l.h.s. bu applying the formula of sin^2A that is 1 - cos^2A
you will be left with the 2cos^2A - 1
therefore cosA=8/17
through this you can calculate sinA using the triangle properties and putting the values in both the sides
you can either do it another way
that is bu solving l.h.s. bu applying the formula of sin^2A that is 1 - cos^2A
you will be left with the 2cos^2A - 1
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