If secA^2 (1+ sinA )(1-sinA ) = k ,then find the value of k .
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Answered by
1
Answer:
secA^2(1-sinA^2)
=secA^2*cosA^2
=1
Answered by
0
HELLO MATE
ANSWER ⏬
sec²A (1+sinA) (1-sinA) =k
[USING (a+b)(a-b) =a²-b²]
sec²A (1-sin²A) =k
[USING cos²A+sin²A=1]
sec²Axcos²A=k
[USING sec²A=1/cos²A]
(1/cos²A) × cos²A=k
k=1
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