Math, asked by raj607513, 1 year ago

If secA^2 (1+ sinA )(1-sinA ) = k ,then find the value of k .​

Answers

Answered by Adbit
1

Answer:

secA^2(1-sinA^2)

=secA^2*cosA^2

=1

Answered by Karthikrikky12
0

HELLO MATE

ANSWER ⏬

sec²A (1+sinA) (1-sinA) =k

[USING (a+b)(a-b) =a²-b²]

sec²A (1-sin²A) =k

[USING cos²A+sin²A=1]

sec²Axcos²A=k

[USING sec²A=1/cos²A]

(1/cos²A) × cos²A=k

k=1

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