if secA= 2/√3 ,
then find the value of
TanA/CosA + 1+SinA/TanA
Answers
Answered by
31
as we know that cos A =1/secA
so by receprocal
cosA =√3/2
cosA=cos 30 degree
A=30
so
tan 30/cos30+ 1+sin30/tan30
1/√3/√3/2+1+1/2/1/√3
by adding you will get 2/3+√3/2
so answer is 4+3√3/6
hope it will help you
so by receprocal
cosA =√3/2
cosA=cos 30 degree
A=30
so
tan 30/cos30+ 1+sin30/tan30
1/√3/√3/2+1+1/2/1/√3
by adding you will get 2/3+√3/2
so answer is 4+3√3/6
hope it will help you
Answered by
25
SecA=2/3
SecA=Sec30
A=30
TanA/cosA+1+sinA/tanA
=tan30/cos30+1+sin30/tan30=2/√3*√3+1+1/2/1/√3
=2/3+3√3/2
=4+9√3/6
SecA=Sec30
A=30
TanA/cosA+1+sinA/tanA
=tan30/cos30+1+sin30/tan30=2/√3*√3+1+1/2/1/√3
=2/3+3√3/2
=4+9√3/6
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