if secA = 2x and tanA = 2/x .find the value of 2(x2 - 1/x2)
Answers
Answered by
186
Hi ,
secA = 2x -----( 1 )
tanA = 2/x ------( 2 )
sec² A - tan² A = 1
( 2x )² - ( 2 /x )² = 1
4x² - 4/x² = 1
4 ( x² - 1/ x² ) = 1
2( x² - 1/ x² ) = 1/2
I hope this helps you.
:)
secA = 2x -----( 1 )
tanA = 2/x ------( 2 )
sec² A - tan² A = 1
( 2x )² - ( 2 /x )² = 1
4x² - 4/x² = 1
4 ( x² - 1/ x² ) = 1
2( x² - 1/ x² ) = 1/2
I hope this helps you.
:)
sayajiraogaikw:
4 ( x² - 1/ x² ) = 1 after that 2( x² - 1/ x² ) = 1/2 ??? plzzz i dont get that only
divide both sides with 2
4/2 ( x² - 1/x² ) = 1/2
is it clear
thnx
u're welcome
Answered by
53
Answer:
In the pic
Step-by-step explanation:
I'm primarily doing this for the points, haha
Attachments:
Similar questions