Question

If secA=41/9,find the other trigonometric ratios of angle A

Answer 1

Step-by-step explanation:

sec A = 41/9 = hyp/adj

using Pythagoras theorem

${hyp}^{2} = {adj}^{2} + {opp}^{2} \\ {41}^{2} = {9}^{2} + {opp}^{2} \\ {opp}^{2} = 1681 - 81 = 1600 \\ opp = \sqrt{1600} = 40$

sin A = opp/hyp = 40/41

cos A = adj/hyp = 9/41

tan A = opp/adj = 40/9

sec A = hyp/adj = 41/9

cosec A = hyp/opp = 41/40

cot A = adj/opp = 9/40

hope you get your answer

Answer 2

Step-by-step explanation:

sec A = 41/9 = hyp/adj

using Pythagoras theorem

\begin{gathered} {hyp}^{2} = {adj}^{2} + {opp}^{2} \\ {41}^{2} = {9}^{2} + {opp}^{2} \\ {opp}^{2} = 1681 - 81 = 1600 \\ opp = \sqrt{1600} = 40\end{gathered}

hyp

2

=adj

2

+opp

2

41

2

=9

2

+opp

2

opp

2

=1681−81=1600

opp=

1600

=40

sin A = opp/hyp = 40/41

cos A = adj/hyp = 9/41

tan A = opp/adj = 40/9

sec A = hyp/adj = 41/9

cosec A = hyp/opp = 41/40

cot A = adj/opp = 9/40