Math, asked by aaina11, 5 months ago

If secA= 5/3
then find
the value of sinA+cosA​

Answers

Answered by Anonymous
0

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sec A= 5/3..........(Given)

Since,

we know that,

Sec=1/ cos

: . Sec A=1/CosA

: . CosA= 3/5

sin²A+cos²A=1....... (formula)

: . Sin²A=1-9/25

: . sinA= 4/5

Therefore,

sinA+cosA=3/5+4/5

=7/5

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