If secA= 5/3
then find
the value of sinA+cosA
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sec A= 5/3..........(Given)
Since,
we know that,
Sec=1/ cos
: . Sec A=1/CosA
: . CosA= 3/5
sin²A+cos²A=1....... (formula)
: . Sin²A=1-9/25
: . sinA= 4/5
Therefore,
sinA+cosA=3/5+4/5
=7/5
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