Question

if secA=5/3 then the value of tan A and cosecA are?​

Answer 1

Answer:

tanA = 4/3 and cosecA 5/4

Step-by-step explanation:

secA - 1 = tan^2A

(5/3)^2 - 1 = tan^2A

25/9 - 1 = tan^2A

16/9 = tan^2A

✓(16/9) = tanA

tanA = 4/3

sin^2A + cos^2A = 1

sin^2A = 1 - 1/sec^2A

sin^2A = 1 - 1/(5/3)^2

sin^2A = 1 - 9/25

sin^2A = 16/25

sinA = 4/5

hence cosecA = 1/sin A

cosecA 5/4