Math, asked by muhor, 10 months ago

if secA=5/3 verify that 4cos3A-3cosA/3sinA-4sin3A​

Answers

Answered by suresh34411
1

13/46

Step-by-step explanation:

cos A = 3/5 (reciprocal of sec A)

sin A = cos²A + 1 = (3/5)² + 1 = 9/25 + 1 = 36/25 = 6/5

Putting these values in the given equation ,

4cos3A-3cosA/3sinA-4sin3A

= 4×(3/5)³ - 3×(3/5) / 3×(6/5) - 4×(6/5)³

= 4×(27/125) - 9/5 / 18/5 - 4×(216/125)

= 108/125 - 9/5 / 18/5 - 864/125

= (108-225)/125 / (450-864)/125

= -117/125 / -414/125

= -117/125 × 125/-414

By cancelling the common factors like 125 , '-' and 9 ,

= 13/46

Hope this will help you.

If so please mark me brainliest.

Similar questions