If secA=5/4.Find the value of sinA-2cosA/tanA-cotA
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Answered by
5
Given secA+tanA=2…. 1
S ince,sec^2A-tan^2A=1
Therefore, secA-tanA=1/2….2
Solving 1and 2
2secA=5/2
SecA=5/4
CosA=4/5
SinA=3/5
. : sinA+cosA=3/5+4/5=7/5
S ince,sec^2A-tan^2A=1
Therefore, secA-tanA=1/2….2
Solving 1and 2
2secA=5/2
SecA=5/4
CosA=4/5
SinA=3/5
. : sinA+cosA=3/5+4/5=7/5
Answered by
3
sec A=5/4
by Pythagoras theorem
5²-4²=x²
x=3
the sides of the triangle=5,4,3
sin A-2cos A (putting value)
3/5 -2(4)/5=-1.......................i
tanA-cotA= 3/4-4/3=-5/12 ............................ii
from i and ii
-1÷-5/12
-1×12/-5=
=12/5
9
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