If seca=5/4 then evaluate tana/(1+tan 2 a).
Answers
Answered by
24
sec a = 5/4
=> cos a = 4/5
=> b = 4, h = 5, p = 3
therefor tan a = p/b = 3/4
hence tan a / (1 + tan^2 a) = (3/4) / (5/4)^2 [ as 1 + tan2a = sec 2 a]
= 3/4 * 16/25 = 12/25
=> cos a = 4/5
=> b = 4, h = 5, p = 3
therefor tan a = p/b = 3/4
hence tan a / (1 + tan^2 a) = (3/4) / (5/4)^2 [ as 1 + tan2a = sec 2 a]
= 3/4 * 16/25 = 12/25
Answered by
4
Answer:
sec a = 5/4
=> cos a = 4/5
=> b = 4, h = 5, p = 3
therefor tan a = p/b = 3/4
hence tan a / (1 + tan^2 a) = (3/4) / (5/4)^2 [ as 1 + tan2a = sec 2 a]
= 3/4 * 16/25 = 12/25
=3/5
Step-by-step explanation:
Similar questions