if seca=5/4then evaluate 1-tana/1+tana
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Answer:
sec a= 5/4
therefore by using identity we find tana
1+ tan²a= sec²a
1+ tan²a=5²/4²
1+tan²a = 25/16
tan²a= 25/16-1
tan²a= 25-16/16
tan²a=9/16
tan a= 3/4
therefore, 1-tan a/1+ tan@
1-3/4/1+3/4
4-3/4/4+3/4
1/4/7/4
1/7
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