Question

if secA+cosecA=b and b(a^2-1)=a then how to prove sinA+cosA=a​

Answer 1

Answer:

secA+cosecA=b

1/sinA+1/cosA=b

1/sinA+1/cosA=a/a^2-1

sinA+cosA/sinAcosA=a/a^2-1

sinA+cosA=a

Answer 2

I Hope if Helped U Answered By Palak Chaplot