If secA=cosecB=12/7, then find the value of A+B.
Answers
Answered by
7
sec=12/7= hypotenuse
perpendicular= base/√H²-B²=√95
TanA=P/B =√95/7
Cosec =H/P=12/7
B=√H²-P² =√95
TanB=7/√95
Tan(A+B)=TanA+TanB/1- tanAtanB
95√7+7√95÷1-95√7×7/√95
=√95/7+7/√95÷1-1
tan90
tan(A+B)=tan90
therefore A+B=90
Answered by
7
Answer:
90
HEY BRO!!
HERE IS UR ANSWER
sec A = cosec B
Using-- sec theta = sec (90°-theta)
sec A = sec ( 90 - B )
A = 90 - B
A + B = 90
HOPE IT HELPS
PLZZ MARK AS BRAINLIEST AND FOLLOW ME
Similar questions