Question

If secA=cosecB=5/3 then find the value of A+B

Answer 1

Answer:

A+B=90°

Sec53°=5/3

Cosec37=5/3

Answer 2

The value of A+B is 90° .

Explanation:

Given : $\sec A=cosec\ B=\dfrac{5}{3}$     (1)

Trigonometric identity :

sec (90°-x) = cosec x  

∴ if cosec B = $\dfrac{5}{3}$

Then, sec (90°-B) = $\dfrac{5}{3}$   (2)

From (1) and (2)

sec A = sec (90°-B) = $\dfrac{5}{3}$

$\Rightarrow\ A=90^{\circ}-B$

$\Rightarrow\ A+B=90^{\circ}$

Hence, the value of A+B = 90°

#Learn more : Hii please answer. ..trigno

https://brainly.in/question/7048787