Question

if seca =root 2and a is in 4th quadrant solve 1+tana+coseca÷1+cota-coseca​

Answer 1

seca = √2 = sec π/4

a in in fourth quadrant

tan a = - tan π/4

= -1

cosec a = - √2

cot a = - cot π/4 = -1

1 + tan a + cosec a - 1 + cot a - cosec a

= 1 - 1 - √2 - 1 - 1 +√2

= 1 - 3

= - 2