if seca =root 2and a is in 4th quadrant solve 1+tana+coseca÷1+cota-coseca
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seca = √2 = sec π/4
a in in fourth quadrant
tan a = - tan π/4
= -1
cosec a = - √2
cot a = - cot π/4 = -1
1 + tan a + cosec a - 1 + cot a - cosec a
= 1 - 1 - √2 - 1 - 1 +√2
= 1 - 3
= - 2
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