Question

if secA-sec²A=-1 then the value of tan²A-tan⁴A is​

Answer 1

Answer:

Given. tan4a+tan2a=1. ⇒(tan2a+1 )tan2a=1. ⇒sec2atan2a=1. ⇒(1cos2a)tan2a=1. ⇒ tan2a=cos2a. ⇒sin2acos2a=cos2a. ⇒sin2a=cos4 ...

Answer 2

Answer:

tan²A–tan⁴A= –1

Step-by-step explanation:

secA–sec²A= –1

secA–( 1+tan²A )= –1

secA–1–tan²A= –1

secA–tan²A= –1 +1

secA–tan²A= 0

secA= tan²A ----------(i)

secA–sec²A= –1

tan²A–(tan²A)²= –1 [from (i) ]

tan²A–tan⁴A = –1