Question

if secA×sinA=0 then find the value of A​

Answer 1

Here, SecA = 1/ cos A

secA × sinA =0 (given)

1/ cosA × sinA=0

sinA/cosA =0

tan A = tan 0 [we used sinA/cosA = tanA, tan 0 =0]

therefore A=0

Answer 2

Answer:

secA(sinA)=0

secA(sinA)=0(1/cosA)(sinA)=0

secA(sinA)=0(1/cosA)(sinA)=0tanA=0

secA(sinA)=0(1/cosA)(sinA)=0tanA=0Therefore A is in 1st or 3rd Quadrant

secA(sinA)=0(1/cosA)(sinA)=0tanA=0Therefore A is in 1st or 3rd Quadranti.e A=0 Degrees, 180 Degrees....

secA(sinA)=0(1/cosA)(sinA)=0tanA=0Therefore A is in 1st or 3rd Quadranti.e A=0 Degrees, 180 Degrees....This yields cosA=1 or cosA=-1