If secA +tan A =p
Find cosec A
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jaspreetjoshan091:
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Given :
sec A + tan A = p
I am replacing p by ' k '
sec A + tan A = k
We know :
sec A = H / B & tan A = P / B
H / B + P / B = k / 1
H + P / B = k / 1
So , B = 1
H + P = k
P = k - H
From pythagoras theorem :
H² = P² + B²
H² = ( H - k )² + 1
H² = H² + k² - 2 H k + 1
2 H k = k² + 1
H = k² + 1 / 2 k
P = k - H
P = k² - 1 / 2 k
Now write k = p we have :
Base = 1
Perpendicular P = P² - 1 / 2 P
Hypotenuse H = P² + 1 / 2 P
Value of cosec A = H / P
cosec A = P² + 1 / 2 P / P² - 1 / 2 P
cosec A = P² + 1 / P² - 1
Therefore , we got value .
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