Math, asked by Anonymous, 10 months ago

If secA+tanA+1=0 then secA-tanA is

Answers

Answered by mysticd

14

Answer:

SecA-tanA = -1

Step-by-step explanation:

SecA+tanA+1=0

=> secA+tanA = -1 ---(1)

=> (secA+tanA)(secA-tanA)=-1(secA-tanA)

=> sec²A-tan²A = -1(secA-tanA)

=> 1=-1(secA-tanA)

=> -1 = secA-tanA

Therefore,

SecA-tanA = -1

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