Question

if SecA- tanA =1/√3
find the value of A​

Answer 1

Step-by-step explanation:

By using identity :sec²A-tan²A=1

Given,

secA-tanA=1/√3 ----eq(1)

(secA+tanA)(secA-tanA)=1

--- a²-b²=(a+b)(a-b)

(secA+tanA)(1/√3)=1

secA+tanA=√3 ----- eq(2)

By adding eq(1) and eq(2)....

2secA=√3+1/√3

2secA=4/√3

secA=2/√3

secA=sec30°

A=30°

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