Question

If secA - tanA= 1/3, the value of (secA+ tanA) is :​

Answer 1

Answer:

$\large\bold\red{3}$

Step-by-step explanation:

Given,

• Sec A - tan A = 1/3

To find,

• sec A + tan A = ?

We know that,

$\large\boxed{\bold{{ \sec }^{2} A- { \tan }^{2} A = 1}}$

Therefore,

We get,

=> (sec A + tan A)(sec A - tan A) = 1

Putting the values,

We get,

=>(secA + tanA ) × ⅓ = 1

=> (sec A + tan A) = 1/⅓

=> (secA + tan A) = 3

Hence,

The required answer is 3.

Answer 2

Given

secA-tanA=1/3

we know

➡sec²A-tan²A=1

➡(secA-tanA)(secA+tanA)=1

➡1/3(secA+tanA)=1

➡secA+tanA=3