Question

If secA-tanA=√2×tanA. Then show that secA+tanA=√2×secA.

Answer 1

Given= secA-tanA=√2×tanA
secA=√2×tanA-tanA
secA=tanA(√2-1)
tanA=secA/(√2-1)............1)

Now ,secA+tanA
secA+secA/(√2-1). {from 1)}
secA(1+1/√2-1)
secA(√2-1+1/√2-1)
secA(√2/√2-1)