if secA+tanA=2 ,then evaluate sinA+cosA==
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Sec^2A-tan^2A=1
(secA+tanA)(secA-tanA)=1
secA-tanA=1/2
secA+tanA=2
2secA=5/2
secA=5/4=hypotenuse/base
so perpendicular=3
sinA+cosA
p/h+B/h
3/5+4/5
7/5
ok plz Mark it as a brainliast
(secA+tanA)(secA-tanA)=1
secA-tanA=1/2
secA+tanA=2
2secA=5/2
secA=5/4=hypotenuse/base
so perpendicular=3
sinA+cosA
p/h+B/h
3/5+4/5
7/5
ok plz Mark it as a brainliast
Anonymous:
plz Mark it as a brainliast
bro
plz Mark it as a brainliast ok
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