Question

if secA+tanA=2, then find the value of (secA-tanA) ?

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if anyone know the best steps to solve this :)

Answer 1

Given Equation is secA + tanA = 2.

We know that sec^2A - tan^2A = 1

We know that a^2 - b^2 = (a + b)(a - b)

⇒ (secA + tanA)(secA - tanA) = 1

⇒ (2)(secA - tanA) = 1

⇒ secA - tanA = 1/2.

Hope it helps!