Question

If secA-tanA=√3, calculate the value of secA+tanA​

Answer 1

Sec^2A-Tan^2A=1

(SecA+TanA)(SecA-TanA)=1

(SecA+TanA)√3=1

SecA+TanA=1/√3

Answer 2

Answer:

1/√3

Step-by-step explanation:

(a^2-b^2)

(a+b)(a-b)

•sec^2 A-Tan^2 A=1

(sec A +tan A)(sec A -tan A)=1

(sec A +tan A)(√3)=1

sec A+tan A=1/√3

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1/√3 in terms of trigonometric ratios is tan 30° or cot 60°...