Question

If secA-tanA=3,is secA+tanA=1/3?how?

Answer 1

If secA – tanA = 3

AS WE KNOW
sec² A - tan² A = 1 

(sec A + tan A)(sec A -tan A)=1 

(sec A + tan A)(3)=1 

(sec A + tan A)=1/3 

Answer 2

If secA – tanA = 3
AS WE KNOW
sec² A - tan² A = 1
(sec A + tan A)(sec A -tan A)=1
(sec A + tan A)(3)=1
(sec A + tan A)=1/3
Hence proved.
May this help u..