Question

If secA+tanA=K
Then senA-tanA=

Answer 1

Answer:

secA-tanA=1/k

Step-by-step explanation:

$secA^{2}-tanA^{2}=1$

$(secA+tanA)(secA-tanA)=1$       $(x^{2} +y^{2}=(x+y)(x-y))$

$secA+tanA=K(given)$

$Therefore,k(secA-tanA)=1$

$SecA-tanA=\frac{1}{k}$

PLEASE MARK BRAINIEST