Question

If seca+tana=m and seca-tana=n find the value of mn

Answer 1

Answer:

sec^a-tan^a

Step-by-step explanation:

mn=( seca+tana)(seca-tana)

Answer 2

Step-by-step explanation:

$\huge\bf{\mid{\overline{\underline{ANSWER:-}}\mid}}$

$\sec(a) + \tan(a) = m \\ \\ \sec(a) - \tan(a) = n \\ \\ multiplying \: \: both... \\ \\ ( \sec(a) + \tan(a) ) \times ( \sec(a) - \tan(a) ) = mn \\ \\ \huge \boxed{{ \sec }^{2} (a) - {\tan}^{2} (a) = mn}$