If secA+tanA=m and secA-tanA=n,then find the value of root mn.
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√(m×n)
= √{(SecA+tanA)×(secA- tanA)}
= √{(secA)^2 - (tanA)^2}
= √1
= 1
I hope this will help you....
= √{(SecA+tanA)×(secA- tanA)}
= √{(secA)^2 - (tanA)^2}
= √1
= 1
I hope this will help you....
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