Question

if secA+tanA=m show that sinA={(m×m)-1}÷{(m×m)+1}​

Answer 1

Answer:

Step-by-step explanation:

if sec a + tan a = m

then sec a - tan a = 1/m

so if we add

2sec a =  m + 1/m

    sec a = m^2 + 1 / 2m                

so cos a = 2m / 1 + m^2                                 sin a = √ 1 - cos^2 a

    so sin a = m^ - 1 / m^2+1