if secA+tanA=p,then prove that sinA=p^2-1/p^2+1
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secA+tanA=p
(secA+tanA)²=p²
sec²A+tan²A+2secAtanA=p²
1/cos²A+sin²A/cos²A+2sinA/cos²A=p²
(1+sin²A+2sinA)/cos²A=p²
{(1+sinA)²}/(1-sin²A)=p²
{(1+sinA)(1+sinA)}/{(1+sinA)(1-sinA)}=p²
1+sinA/1-sinA=p²
Now,place the value of p² in the equation.
{(1+sinA/1-sinA)-1}/{(1+sinA/1-sinA)+1}
=SinA(proved)
(secA+tanA)²=p²
sec²A+tan²A+2secAtanA=p²
1/cos²A+sin²A/cos²A+2sinA/cos²A=p²
(1+sin²A+2sinA)/cos²A=p²
{(1+sinA)²}/(1-sin²A)=p²
{(1+sinA)(1+sinA)}/{(1+sinA)(1-sinA)}=p²
1+sinA/1-sinA=p²
Now,place the value of p² in the equation.
{(1+sinA/1-sinA)-1}/{(1+sinA/1-sinA)+1}
=SinA(proved)
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