Question

if secA+tanA=p,then secA-tanA=​

Answer 1

Answer:

$given = \sec(a) + \tan(a) = p \\ \\ to \: find = \sec(a ) - \tan(a) \\ \\ amswer \: is \: = = > > p$

$hope \: it \: helps \: you$

Answer 2

⁸

Answer:

1÷p

Step-by-step explanation:

(secA+tanA)(secA-tanA)=1

(p)(secA-tanA)=1

secA-tanA=1/p