Question

If secA +tanA =x, find the value of secA-tanA in terms of x.

Answer 1

Answer:

Step-by-step explanation:we have secA+tanA=x

Therefore,sec²A+tan²A+2tanAsec=x²

2tan²A+1+2tanAsecA=x²(since,sec²A=tan²A+1)

2tanA(tanA+secA)=x²-1

Hence tanA=x²-1/2x

Similarly,secA=x²+1/2x

Therefore ,secA-tanA=x²+1-x²+1/2x

That would simplify as secA-tanA=1/x

Answer 2

Answer:1/x

Step-by-step explanation:we have secA+tanA=x

Therefore,sec²A+tan²A+2tanAsec=x²

2tan²A+1+2tanAsecA=x²(since,sec²A=tan²A+1)

2tanA(tanA+secA)=x²-1

Hence tanA=x²-1/2x

Similarly,secA=x²+1/2x

Therefore ,secA-tanA=x²+1-x²+1/2x

That would simplify as secA-tanA=1/x

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